IF KAMAL Is Written As 21413, Then MAHAL Can Be Written

From KAMAL = 21413 we get a fixed letter-to-digit code: K=2, A=1, M=4, L=3. The same letter always gets the same digit, so MAHAL should read 4 1 ? 1 3, with the third digit standing for H.

H never appears in KAMAL, so its code cannot be read off directly. We have to test each option for consistency with the known codes.

• A) 48113 is wrong. The second letter A would be coded 8, but A is already 1 in KAMAL.
• B) 41813 is correct. M=4, A=1, H=8 (a new digit, which is allowed), A=1, L=3. Every known letter matches.
• C) 41831 is wrong. The final letter is L, which must be 3, but this option ends in 1. The A in the fourth place is also coded 3, which conflicts with A=1.
• D) 38141 is wrong. M would be 3, but M is 4 in KAMAL.

The core concept is substitution coding, where each letter maps to one digit consistently. Questions like this test whether you can use partial information and eliminate options quickly, which is the same skill used in logical reasoning and CSAT-style sections.

Trap: Aspirants try to decode H and get stuck. Check the letters you can decode first and eliminate the options that break them.