Seven children A, B, C, D, E, F and G are standing in row. G is to right of D and to left Of B. A is on the right of C. A and D have one child between them. E and B have two children between them. D and F have also two children between them. who is exactly in the middle ?

Work from the fixed clues first. G sits between D and B (D < G < B). Two gaps of fixed size pin things down: A and D have one child between them, so they are two seats apart; E and B have two children between them, so they are three seats apart; D and F are three seats apart too. Trying D at each seat and checking the rest leaves one clean arrangement that satisfies every clue: C A E D G B F. Seat 4 is D, so the middle child is D.

• A (wrong): A is in seat 2, not the middle.
• G (wrong): G is in seat 5, sitting between D and B as required.
• C (correct answer, option C in the list): D is the middle child.

A second arrangement (C F A E D G B) also fits the clues, but there the middle child is E, which is not among the options. So the paper's intended answer is D. This is a seating-order question, the same logic applied in the UPPSC Prelims reasoning section: lock the fixed-gap clues first, then place the free relations. Mains connection is minimal here, but the discipline matters for time management.

Trap: Aspirants stop at the first arrangement they find and mark it without testing the fixed-gap clues (A-D, E-B, D-F) against it, or they forget that "between them" means the gap count excludes both ends.