UPPSC PCS - 2014

A Postman walked 7 kms. North from the post office to reach Mr. Singh’s house. He took a left turn and walked 4kms. To reach Mr. kumar’s house. he then took a right turn and walk 3kms. To reach Mr Sharma house the distance between Mr Sharma and Mr. Singh’s house is

Year Asked: 2014

A
5 kms.
B
6 kms.
C
4 kms.
D
7 kms.

Correct Answer

A. 5 kms.

Detailed Explanation

The correct answer is A. Place the post office at the origin. The postman walks 7 km north to Mr. Singh's house, so Singh is at (0, 7). Facing north, a left turn means heading west. Walking 4 km west takes him to Mr. Kumar's house at (-4, 7). A right turn from west means heading north, and 3 km more brings him to Mr. Sharma's house at (-4, 10).

The distance between Sharma and Singh is the straight line joining them, which forms a right-angled triangle with legs of 4 km (east-west) and 3 km (north-south). By Pythagoras, the hypotenuse is √(16+9) = 5 km. This is a direction-and-distance problem of the kind reasoning sections test repeatedly, and the same coordinate method works for every such question.

  • Option B (6 km) and Option D (7 km) ignore the geometry of the turns and simply add or repeat legs of the path.
  • Option C (4 km) takes only the westward leg, which is the distance from Kumar's house to Singh's house, not Sharma's.

Trap: adding 4 + 3 = 7 km, or stopping at the total distance walked, instead of finding the straight-line displacement. Always sketch the path and join the start and end points.

This question appeared in UPPCS 2014 GS Paper 2.

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