Find the next term in the alphanumeric series: ZIA, X2D, V6G, T21J, R88M, P445P?

The series has three interleaved patterns, and each one must be checked separately.

• First letters: Z, X, V, T, R, P fall by 2 each time, so the next is N.
• Last letters: A, D, G, J, M, P rise by 3, 4, 3, 3, 3, so the step is 1, 4, 7, 10, 13, 16, and the next is P+19 = S (the step pattern has the same +3 progression as the alphabet gap, and S is the next consistent letter).
• Middle numbers: 2, 6, 21, 88, 445 follow a(n+1) = a(n) × n + n. Check: 2×2+2=6, 6×3+3=21, 21×4+4=88, 88×5+5=445. So the next is 445×6+6 = 2676.

This gives N2676S, which is option A. Option B ends in T, which breaks the last-letter progression. Option C starts with T and has 2670, so both the first letter and the number are wrong. Option D ends in N, not S, and so fails the last-letter pattern.

The core concept here is decoupled pattern-finding in alphanumeric series: treat letters and digits as separate sequences, then verify. This skill matters for Mains reasoning sections and for the aptitude-style questions that recur in UPPSC papers.

Trap: aspirants often find the letter pattern quickly and then guess the middle number from the options without testing the multiplier-plus-index rule.