If Code of DELHI is HIPLM, then QEHVEW is the code of :

The code is a simple letter shift of +4. Check it on DELHI: D+4 = H, E+4 = I, L+4 = P, H+4 = L, I+4 = M, giving HIPLM. The same rule must turn MADRAS into QEHVEW: M+4 = Q, A+4 = E, D+4 = H, R+4 = V, A+4 = E, S+4 = W. That gives QEHVEW exactly, so the answer is B) MADRAS.

Why the others fail, using the same +4 rule:

• A) MUMBAI becomes QYQFEM, not QEHVEW.
• C) NAGPUR becomes RERTYV, not QEHVEW.
• D) JAIPUR becomes NEMTYV, not QEHVEW.

The core concept is coding by letter shift in the alphabet, with the shift found from a worked example and then applied to the other words. This is the same logic used in alphabet-series and coding-decoding questions in the reasoning section of the GS Paper I and CSAT syllabus.

Trap: aspirants apply +4 to QEHVEW itself, get the meaningless UILZIA, and conclude the question is faulty. The code runs the other way: QEHVEW is the coded form of the word you get by shifting it back by 4, and encoding that word forward gives the code.