If x, y, z are positive integers such that x:y = 1:2 and y:z = 3:5, then which one of the following will be possible value of 5x-3y+z?

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CollectorBabu · Accepted Answer

Correct Answer: 196. (x: y = 1: 2, y: z = 3: 5 SO, x: y: z = 3: 6: 10 ⇒ Lets say, (x, y, z) = (3k, 6k, 10k) Now, 5x – 3y + z = 5 × 3k – 3 × 6k + 10k = 7k. From given option only 196 is divisible by 7. One of the possible value is 196. Hence option C is correct answer.

If x, y, z are positive integers such that x:y = 1:2 and y:z = 3:5, then which one of the following will be possible value of 5x-3y+z?

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