The age of father is twice that the sum of ages of his two sons. 20 years later, the age of father will become the sum of ages of his two sons. The present age of father is

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CollectorBabu · Accepted Answer

Correct Answer: 40 years. Given, The age of father (F) is twice that the sum of ages of his two son (S1 and S2) Hence, F = 2(S1 + S2) S1 + S2 = F/2…………………1 20 years later, the age of father will become the sum of ages of his two sons- Hence After 20 years, age of father is F + 20 Age of his sons will be, S1 + 20 and S2 + 20 So, F+20 = (S1+20) + (S2 + 20) F + 20 = S1 +S2 + 40 F = S1+S2 +20……………..2 From 1 and 2 we get, F = F/2 + 20 F/2 = 20 F = 40 Hence option A is correct answer.

The age of father is twice that the sum of ages of his two sons. 20 years later, the age of father will become the sum of ages of his two sons. The present age of father is

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